c++ - Why is the output of this code is 22? -

c++ - Why is the output of this code is 22? -

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why output of code 21 , not 12? [duplicate] 2 answers #include <iostream> using namespace std; class { int *val; public: a() { val = new int; *val = 0; } a(a &a) { val = new int; *val = a.get(); } int get() { homecoming ++(*val); } }; int main() { a,b = a; cout << a.get() << b.get(); homecoming 0; }

i have problem working out. getting confused on how *val gives output of 22 both object.

it's simple. create a has *val set 0.

then create b via b = a, invokes re-create constuctor. re-create constructor calls a.get().

a::get() increments value pointed val 1 , returns it. a gets *val set 1, , b gets value , sets own *val 1.

then print both using get() 1 time again increases each before returning. 2 both gets on cout << a.get() << b.get();.

i don't know reason why val int* instead of int obfuscates code, , makes harder grasp beginner.

c++