regex - Replace repeating character with another repeated character -



regex - Replace repeating character with another repeated character -

i replace 3 or more consecutive 0s in string consecutive 1s. example: '1001000001' becomes '1001111111'.

in r, wrote next code:

gsub("0{3,}","1",reporting_line_string)

but replaces 5 0s single 1. how can 5 1s ?

thanks,

you can utilize gsubfn function, can supply replacement function replace content matched regex.

require(gsubfn) gsubfn("0{3,}", function (x) paste(replicate(nchar(x), "1"), collapse=""), input)

you can replace paste(replicate(nchar(x), "1"), collapse="") stri_dup("1", nchar(x)) if have stringi bundle installed.

or more concise solution, g. grothendieck suggested in comment:

gsubfn("0{3,}", ~ gsub(".", 1, x), input)

alternatively, can utilize next regex in perl mode replace:

gsub("(?!\\a)\\g0|(?=0{3,})0", "1", input, perl=true)

it extensible number of consecutive 0 changing 0{3,} part.

i don't endorse utilize of solution, though, since less maintainable.

regex r

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